360=108x+x^2

Solution for 360=108x+x^2 equation:

360=108x+x^2

We move all terms to the left:

360-(108x+x^2)=0

We get rid of parentheses

-x^2-108x+360=0

We add all the numbers together, and all the variables

-1x^2-108x+360=0

a = -1; b = -108; c = +360;
Δ = b2-4ac
Δ = -1082-4·(-1)·360
Δ = 13104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13104}=\sqrt{144*91}=\sqrt{144}*\sqrt{91}=12\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-12\sqrt{91}}{2*-1}=\frac{108-12\sqrt{91}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+12\sqrt{91}}{2*-1}=\frac{108+12\sqrt{91}}{-2}
$